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1. Present Data

The following bar graph displays the result of 100 completely random coin flips; these coin flips represent the random variation affecting one’s probability of having a girl or a boy child. In this experiment, Drew and I were testing the idea that Ms. Williams could be wired for boys after having three sons in a row. When the quarter was flipped, tails represented girls and heads represented boys.

tara_coin_flip.gif

As you can see in the graph, the number of times that tails (girls) came up when the quarter was flipped greatly exceeds the number of times heads (boys) came up, by a ratio of 64-36. Therefore, according to the results of this particular experiment, Ms. Williams is actually not wired for boys at all simply because she was found to have more girls than boys due to random variation.

2. Provide Answers To Questions Related to Weekly Topic

a. Making Inferences From Small Samples

# times coin came up tails: 64/100 = 64 girls

# times coin came up heads: 36/100 = 36 boys

# times 3 heads (boys) came up in a row: 3 = S

# times possible that 3 heads (boys) could come up in a row: 98 = 100-(3-1)

Based on this experiment, the probability of having three heads come up in a row is only 3%. This percentage was found by dividing the value of S by 98, as stated above, and multiplying by 100. Therefore, since Ms. Williams did indeed have three boys in a row, she fits into this small percentage. However, it is not safe to say that she is “wired” for boys because this particular experiment also reflects that random variation can cause an abundance of one side (girls) over another (boys) of a normally 50/50 chance event (girls or boys). If we flipped the quarter 10,000 times instead of only 100 times, the occurrence of heads (boys) would rise. Likewise, the occurrence of tails (girls) would steadily decrease, thus creating a proportion of boys v. girls closer to 50%.

b. The Principle of the Law of Large Numbers 

One example of where the law of large numbers affected me was when I developed a brief devotion to Outback Steakhouse.  I had not been to the restaurant for years.  I went to eat there, enjoyed the food, and went back three more times in the next year.  However, when I went the fourth time, I acquired a bad case of food poisoning.  I even got a phone call from the restaurant a week later as an apology (apparently many people who ate there that night had been poisoned by tainted seafood).  Nonetheless, I have never been back to the restaurant due to this bad memory.

My example illustrates one condition in which I would make a mistake in judgment.  I may have gotten poisoned the fourth time I went to the restaurant, but this certainly does not mean that people who go to Outback have a 25% chance of being served tainted food.  Despite the fact that I could acknowledge this reasoning, I still remained aversive to going back, as if the probability of 1:4 was possible.  I made an error about the situation, similar to that of the mother who had only boys and that of the orange inspector from our class assignment paper. 

Going to Outback again was probably not going to result in another bad experience, yet I had a fixed impression of the event just like the orange inspector thought all the oranges were bad and the mother thought that she could not have girls.I also could have experienced other rare conditions at Outback that would have affected my judgment of the restaurant.  For example, the oven could have broke and we would have not received a meal, the server could have brought us the wrong dishes and we may have received the original meals for free as a result, or we may have driven to the restaurant to discover that they were closing down and we would have to leave.  All of these potential influences could affect my judgment of the restaurant, because they are rare events and are extreme cases.  If any of these events occurred in the four times I went to Outback, then I would have a rare event in a small sample size.  With less experience going to the restaurant, I would be prone to thinking that such an unusual event was the norm (even if I knew otherwise that this was not the case).

Standard deviation formula: SD=square root (sum of a given variable X minus the mean squared) /n or the number of times the event occurred

Assuming that n is the only variable that changes when comparing two SD equations, the equation where n equals a smaller number will equate to a larger end answer.  This is due to the fact that a greater bottom value (a larger sample) results in a smaller answer (less variation), than does a tiny bottom value (a smaller sample) with the same top value sum which results in a larger answer (more variation).

c. Proportion of Males in Class v. Male Psychology Majors (nationwide)

Professor MacEwen mentioned that “there are 8 males in our class out of 46 total people”.  However, I found from a web article that “73% of bachelor’s degrees awarded in psychology were given to women”.  The article titled “Major Conclusions” proceeded to conclude that “within psychology graduate programs, women constitute the majority” (Major Conclusions).

8/46 = .1739            73/100 =  .7300   

Despite the fact that the article is out of date (the figure of 73% was from 1991), the article mentions the trend of females roles in psychology increasing and surmises that their numbers among psych majors will continue to rise as the number of men declines.  Therefore, the lower frequency of males in our class could be due to the fact that, over a period of about two decades, men’s numbers in psych programs have indeed experienced a dramatic reduction.  However, the results may not have been related to nationwide trends, but instead to state college trends or even differences in various psych classes.  For instance, do other Virginia colleges have more or less psych majors who are males?  Does our statistics class happen to have a disproportionately high or low amount of males relative to all the males who are currently majoring in psych at UMW?

As demonstrated in class with the law of large numbers, we may be obtaining an inaccurate sample.  For instance, if our class ratio of males to total students is 8:46 and there are only 10 male psych majors currently at UMW than our sample would be disproportionately inaccurate.  However, if there were 200 pysch majors who were male, our sample may be unrepresentative as well, since it would be abnormally low instead of abnormally high.  Also, the proportion of psych majors at UMW compared to other VA schools might be higher or lower.

d. Using Z-Scores

# miles I waited to change oil: 3467 miles

Mean # miles people wait to change oil: 3258 miles, SD = 223 miles

When first addressing this debate with my father, given the statistics listed above, I would initially argue that I chose to change my oil well within one standard deviation of the population mean. When looking at the structure of the normal distribution curve, I would show my dad that 68% of people will change their oil between 3035-3481 miles:

Population mean (3258) +/- standard deviation (223) = 1 SD (3035-3481)

Therefore, choosing to change my oil at 3467 miles falls within one positive standard deviation of the population mean. When using the Z-table, we first had to convert our mileage into z-scores, aka standard scores. We plugged in our values as follows:

Z = (x-value – population mean) / SDZ = (3467 mi. – 3258 mi.) / 223 mi. = 0.9372

After obtaining 0.9372 as the z-score, I rounded it off to 0.94 and then moved to the z-table provided on blackboard to find the area between the mean and our z-score. When looking at the table, a z-score of 0.94 correlated with an area of 0.3264. So, speaking in terms of probability, it can be said that 0.3264 of scores fall between the mean (3258 mi.) and a z-score of 0.94 (3467 mi.). To convert this percentage, I used the following formula:

% = (probability)(100) % = (0.3264)(100) = 32.64%

Therefore, in this particular argument with my father, I would tell him that 17.36% of people wait longer than I did to change my oil. To find this value, I simply subtracted 32.64% from 50% (the area above the mean).

3. Relation to Statistical Topic From Class

This experiment exemplifies the fact that despite randomness, most events occurring in the world today will develop a normal or bell-shaped curve. This frequency distribution is theoretical in the sense that it only occurs in our mind, although we can make educated inferences based upon it. A normal frequency distribution can be converted into a probability distribution by simply converting percentage into probability, as outlined earlier. This procedure was put into practice in the earlier examples. By finding the probability distribution, as was done in part (d) of section 2, the area under the distribution curve can also be found, making for easy comparison. Because we are usually given the standard deviation scores, which are not convertible in probability distributions, we must convert them into standard scores, aka z-scores. By using the equation listed above to calculate z-scores, we can then look at the z-table to find the corresponding area. Again, part (d) of section 2 put this concept into practice.

4. Weaknesses/Limitations and Strengths

Flaws/Weaknesses: Girls came up significantly more frequently than boys in the sample of 100 coin tosses (64 vs. 36), which is not close to the 50-50 chance that it should be around.  Also, boys appeared 3 times in a row only on 3 occasions.

Strengths: From the data we collected, it can still be concluded that Mrs. Williams can in fact have girls.  Our data also explain how Mrs. Williams could have figured that she could only have boys (she fits into the scenario of those 3 cases where boys appeared 3 times in a row).

5. References

1. Unknown Author.  “Major Conclusions”  http://www.apa.org/pi/taskforce/majorconcl.html

2. MacEwen, Professor.  PowerPoint presentations (lectures from 1/30, 1/31, and 2/4) 

 The graph below charts both of our temperature values.  Tara’s temperature values are represented in blue, my temperature values are represented in pink.  Gaps in the graph show where recordings are missing.  The temperatures were recorded over a range of ten days (although no temperatures were taken from 1/22 to 1/24).  Therefore, temperatures were measured over seven days for Tara and six for me, as I have no readings for 1/19 as well.  Each point on the graph represents one temperature reading.  Points range from Tara’s high of 99.1 degrees to my low of 92.8 degrees.

Tara and Drew Temperature Fluctuation Graph   

3. Present Data

The following table displays the statistics of our original temperature recordings collected from Thursday, Jan. 17th through Monday, Jan. 21st, as well as our additional recordings collected from Friday, Jan. 25th through Saturday, Jan. 26th.  There are a total of 38 temperature readings taken for Tara, and 18 for Drew. There is a breakdown of both the central tendency values (mean, median, and mode) and the variance values (standard deviation and variation) for these recordings, as calculated by SPSS.

Statistics  (SPSS)

Tara Temperature Values Drew Temperature Values
N Valid 38 18
  Missing 1 21
Mean 97.932 96.133
Median 98.100 96.250
Mode 98.0(a) 96.0(a)
Std. Deviation .8712 1.4951
Variance .759 2.235

a  Multiple modes exist. The smallest value is shown

2. Relate It To The Statistical Topic From Class

The following calculations were done by hand, thus confirming the values already calculated by SPSS. These calculations include the additional values taken from Friday, Jan. 25th- Saturday, Jan. 26th.   

Tara 

Central Tendency 

Mode: Unlike the mode from only the original values, there are two temperature readings that occur equally and most frequently. They are 98.0 and 98.2 degrees Fahrenheit. Other frequently occurring temperatures included 98.3, 98.6, and 98.9.  

Median: Because there were a total of 38 values, the exact middle value was actually a tie between the 19th and the 20th values. Therefore, it was necessary to find the average of these two values. Because the 19th value was the same as the 20th value (98.1), the average was also the same. 

Mean: By adding up each individual temperature reading (3721.4) and dividing by the total number of temperature readings (38), I found the arithmetic mean of my temperature readings to be 97.932.

Variation 

Standard Deviation: By taking the square root of the variation, I then calculated the standard deviation of my temperature fluctuation. I found the standard deviation to be about 0.86.

Variation: I calculated the variation of my temperature fluctuation to be about 0.74.

Drew

For all 18 values

Central Tendency: Includes mean, median, and mode.

Mean: 96.1

I obtained the mean by adding all the temperature values and then dividing that sum by 18. 

Median: 96.25

I put all of my temperature values in order from the lowest to the highest temperatures and found that 96 and 96.5 were the two middle values.  Since there cannot be two medians, 96.25 was the median, because it lies equally between these two values.

Mode: 97.6 and 96 (bimodal)

I determined the mode by finding out which temperature values occured most frequently.  Since 97.6 and 96 occured twice and all my other temperature values occured only once, these two values were my modes.  Therefore, I had a bimodal arrangement, similar to Tara, who had two modes which appeared four times each.

Variance: Includes standard deviation and variance. 

SD: 1.4533

To find the standard deviation, I took the square root of the variance (2.1122).

Variance: 2.1122

To find the variance, I used the formula: the square root of the sum of any given value minus the mean value squared divided by the total number of temperature readings.  n=18, because I had 18 total readings.  The X mean value was 96.1 degrees.  The X variable represented one of the 18 values that I used to plug into the equation.  After I solved the X mean minus the X certain variable using all the values, I took the sum of all 18 of these differences after they had each been squared.  This yielded a value of (38.02).  I divided 38.02 by the number of total readings (18) to get my variance of (2.1122).      

3. Present Data

The following table displays only the statistics of our original temperature recordings; that is, the data points collected from Thursday, Jan. 17th through Monday, Jan. 21st.

Statistics (SPSS)

Tara Drew
N Valid 32 12
Missing 1 21
Mean 97.894 96.400
Median 98.100 97.100
Mode 98.0 97.6
Std. Deviation .9370 1.7273
Variance .878 2.984

2. Relate It To The Statistical Topic From Class

The following calculations were done by hand, thus confirming the values already calculated by SPSS. Once again, these calculations are for our original values, and do not include the additional temperature recordings that were taken later in the week to help support our findings. These calculations also include explanations as to how they were found.  

Tara 

Central Tendency 

Mode: the most frequently occurring score; this value was easily found by simply listing all 32 values in order from least to greatest, and picking out the one that occurred the most. 98.0 degrees Fahrenheit was recorded on four different occasions between Thursday, Jan. 17th and Monday, Jan. 21st, most often during the later afternoon-early evening hours. This value also agrees with the calculations found for the mode by SPSS. Other frequently occurring temperatures included 98.2, 98.6, and 98.9 

Median: the exact middle score; this value was easily found as well by listing all 32 values in order from least to greatest. Because there were a total of 32 values, the exact middle value was actually a tie between the 16th and the 17th values. I was able to find this by plugging in 32 for the value of “n” in the equation (n+1)/2. Therefore, it was necessary to find the average of these two values. Because the 16th value was the same as the 17th value (98.1), the average was also the same. The value of 98.1 degrees Fahrenheit agrees with the calculations found for the median by SPSS. 

Mean: the most representative of all the values; this value has a little more work involved in order to be calculated by hand. By adding up each individual temperature reading (3132.6) and dividing by the total number of temperature readings (32), I found the arithmetic mean of my temperature readings to be 97.894. This value agrees with the calculations found for the mean by SPSS. 

Variation 

Standard Deviation: arithmetic average departure/deviation from the mean; this value was tedious to calculate, as there are several steps in obtaining the final result. By plugging in each individual temperature reading for “x” in the equation (x-mean) squared, I was able to calculate each value’s individual deviation from the mean. I then added each of those values together and divided by the total number of values (32) to find the variation. By taking the square root of the variation, I then calculated the standard deviation of my temperature fluctuation. I found the standard deviation to be about 0.922, thus differentiating itself from the calculated SPSS value for the standard deviation of 0.937  

Variation: how much the data values depart from the mean of the whole set of data values; as stated earlier, this value is found before the square root is taken in the equation above. And so, I calculated the variation of my temperature fluctuation to be about 0.851, thus differentiating itself from the calculated SPSS value for the variation of 0.878.

Drew

For the first 12 values (as they are included in the previous post)

Central Tendency 

Mean: 96.4

Median: 97.1

Mode: 97.6

Variance

SD: 1.6538

Variance: 2.735

1.              Provide Definitions/Answers to Questions Related to the Weekly Topic 

Tara

Of the three measures of central tendency, the mean is most influenced by extreme temperature values. Because the mean is the summation of all the temperature values divided by the total number of temperature values, any extremity (high or low) is going to greatly affect the overall outcome of the equation. For example, in my temperature readings, there are two extremities present: a low of 95.3 and a high of 99.1. When calculating the mean of my temperature readings, the disparities exhibited with these two temperatures will change the outcome from what it would have been if those two temperatures had been closer to the average.

These extremes could have occurred for any number of reasons. One reason could be the fact that when the 99.1 degrees Fahrenheit was recorded, I had just sipped a cup of hot coffee. Perhaps when I took my temperature and recorded 95.3 degrees Fahrenheit, the thermometer had been sitting next to an open window, thus chilling it more so than it would have been if not seated by the window. I do not think that extremes in temperature fluctuation are uncommon, especially since there are so many outside factors that could affect the outcome, like the reliability of the thermometer itself. Considering that my most extreme temperatures were still within 5 degrees of the average, I think these can be easily explained. I do think there should be less reliance upon these extreme values since the majority of the rest of the values fall between 97-99 degrees Fahrenheit. Obviously, the more data points that are collected, the more chances there are for extreme values to be present. Therefore, we can probably count on the fact that during some parts of the day our body temperatures are lower than usual, such as early in the morning, and other parts of the day they may be higher, such as later in the afternoon.

According to the article by Allen Shoemaker, the actual population mean for body temperature is 98.2 degrees Fahrenheit, as opposed to the originally accepted value of 98.6 degrees Fahrenheit. Shoemaker explains that the previous temperature mean of 98.6 degrees Fahrenheit is one hundred years outdated, as it was calculated by Carl Reinhold August Wunderlich. Because of problems with Wunderlich’s original methodology, diurnal fluctuations, and unreliable thermometers, Shoemaker and others argue that it is extremely necessary for students to reevaluate this initial finding.

My average body temperature, based on the 38 temperature readings I took over a period of ten days, is about 97.9 degrees Fahrenheit. When compared to the average body temperature stated in the article (98.2 degrees Fahrenheit), my average is 0.3 degrees lower. According to the standard deviation in the article (0.73 degrees Fahrenheit), my average is well within one standard deviation of the population mean: 98.2 +/- 0.73 = a range of 97.5-98.9 degrees Fahrenheit It seems that my average body temperature is not the unusual according to the findings of Shoemaker’s article.

It is interesting to note that my mean body temperature is actually lower than the population mean, because women tend to have higher body temperatures than men and my statistics contradict this idea. In fact, men are “cooler” than women, on average, by 0.1-0.2 degrees Fahrenheit. Drew’s mean as well as mine confirm this idea, since his average body temperature is 96.1 degrees and mine is 97.9 degrees. Obviously our findings greatly exceed the average difference of temperatures between men and women: 97.9 (Tara’s mean temp.) – 96.1 (Drew’s mean temp.) = 1.8 degree difference 

I do not think our body temperatures are representative of the population simply because Drew’s recordings greatly differ from the findings stated in the article. Not only does his mean temperature lie well outside one standard deviation from the population mean stated in the article, but he has several extreme temperatures that also defy this norm. I do not necessarily believe that if we both continued taking our temperatures throughout the remainder of the semester, it would hinder a more accurate response in comparison to the population mean and standard deviation simply because it seems that Drew’s body temperature is actually that low in reality.  

Conversion of degrees Fahrenheit to degrees Celsius:

            (97.9-32) * 5/9 = 36.6 degrees Celsius

Drew

Part 1:   Out of the three measures of central tendency, the mean is the most likely to be influenced by extreme outlier temperatures.  This is due to the fact that extreme values can “pull” the mean in different directions.  For example, in our class notes, we discussed what the difference of the mean would be in a group of IQ scores 100 and 110, and a group of scores including 100, 110, and 110.  Although the outliers presented are not extremes or great in number for this example, the effects on the mean can still be noted as the extra 110 score “pulls” the mean above 105.  When there is more data, the number of outliers in a given direction make a more pronounced difference, especially if they are more extreme.  The extreme temperature readings I obtained may have occured for reasons I will highlight below when I mention the article.  In the case of my temperature, the extremes were not unusually rare (with the exception of 92.8), as I had several readings close together that fell below 96 degrees.  I am not sure these extremes were reliable however, as I could have made an error while taking my temperature or the thermometer could have been malfunctioning.

Part 2:      Based off of the conclusions from the article on temperature, it is easy to see how our mean temperatures fell below 98.6 degrees.  Also, Tara had higher readings than I did, because she is a female, and females tend to have higher body temperatures than males.  However, I believe my extremely low mean temperature may be due in part to a number of other factors.For example, the fact that it is winter time and the temperature is cold outside probably had the effect of lowering my body temperature, especially since I have gone outside wearing shorts from time to time, when going back and forth from the gym.  Additionally, I had a cheap thermometer, I showered infrequently(warm water raises temperature), I may not have placed the thermometer far enough back in my throat, or I may not have completely closed my mouth when taking some of the readings.  While the exact reason is not certain, my average temperature is certainly far below the typical average temperature for males (98.1).98.1-96.1=2 SD from article=.73

Part 3: Based on the SD from the correct average temperature in the article (.73), my difference of 2 falls well outside of the average and outside of the first standard deviation from the mean temperature (98.1).  My abnormal temperature goes far beyond the fact that I am a male, because the .1 to .2 difference between genders is minimal compared with a difference of 2.  Therefore, living conditions, internal body regulation, or other factors may have an impact on the bizzare mean.My body temperature was below that of Tara.  However, despite the fact that she is a female, my data still seems inaccurate (my average temperature should be significantly higher).  If I were to continue taking my temperature, I think my readings would change because of the springtime.  The  weather would get warmer, which would effect my temperature readings, making them increase, and as a result, they would be more accurate in being closer to 98.1 (the average temperature for males).

Formula for converting Farheinheit to Celsius: C = (degrees F – 32) * 5/9

My temperature of 96.1 degrees F in Celcius: 35.61 C

5. Suggest Flaws/Weaknesses as well as Strengths  

Flaws/Weaknesses: One of the major flaws that existed in the collection of our data was the fact that there was a significantly large time discrepancy between when the original data points were recorded (1/17-1/21) and when the additional six were recorded (1/25-1/26). Any number of factors could affect the reliability of these additional data points. For example, a dramatic change in the temperature outside between the days the temperatures were taken could have an effect on either partner’s body temperature. However, the benefits of having additional data points outweigh the flaws.  

Strengths: Although the additional temperature readings produced minor flaws, they also provided more support for our findings. Having a total of 38 temperature values for Tara and 18 for Drew allowed both partners to conduct a more comprehensive and detailed report than they would have with only the original temperature readings.

4. Identify Sources or References Used 

MacEwen, Professor. Notes: “Assignment Two: Order from Chaos- Measures of Central Tendency and Variation.” 2008. 

MacEwen, Professor. PowerPoint Presentation: “Variation and Randomness.” 2008. 

Shoemaker, Allen L. What’s Normal? Temperature, Gender, and Heart Rate. Journal of Statistics Education. 4, 2 (1996).

2. Is it possible to predict what the next temperature value would be or correctly predict any future event? Why or why not?

It is not possible to predict what my next temperature reading would be if I were to take it again, because numerous random events will have an effect on the future results. For example, I might have a certain temperature reading due to amount of sleep, type of thermometer, accuracy of thermometer, food I ate, amount of exercise I engaged in during the day, time of day of the next reading, and so on. It is impossible to account for all the possible variables which could influence the result. This same principle applies to all other events as well. Assuming that we can predict a future event is assuming the future is certain. This is obviously a fallacy.

4. Identify at least 7 other sources of random variations that affect your life. How do these sources affect you?

1. Quality of relationships with other people:

If a friend, family member, or romantic partner is in a bad mood, then it will influence your mood and if they are feeling upbeat, then their cheer will likely “rub off” on you as well.

2. Grades attained/School success (an example taken from class)

You only have some control over the grades you get. Class structure, professor’s agenda, and whether or not you have close friends or peer support in the class also plays a role, which you can’t control.

3. Athletic performance

Athletic performance can be improved with practice. However, due to lack of sleep, stress, or inadequate hydration, you may have an off day now and then.

4. Occupational attainment (taken from class notes)

The job you recieve can be influenced by your level of educational attainment. However, you may not get a desirable job because you lack outside support, you disagree with the boss, you decide you don’t like the job environment, you lack certain personality traits the boss finds desirable in employees, and other factors.

5. Dream content

Your dream content affects you in that nightmares may increase levels of fear or panic in their aftermath and good dreams may lead to an elated mood in the moments in “the wake” of the dream. A dream might effect your mood the next day, and in turn, your mood might influence your experiences that day.

6. Economic stability

Your economic stability effects you drastically. No matter how poor you are, you could theoretically become very rich by chance in the next year, month, or even day. The likewise holds true for the rich in terms of their risk of becoming poor. However, the chances of either scenario actually occuring are very minimal, but they are nonetheless remotely possible.

7. Government policies

Government policies may have a direct effect on citizens. However, their indirect effects are also exceptionally important. People may support certain candidates with the conscious or unconcscious notion that a candidates’ sucess will change certain indirect influences in their lives.


Psychology Picture
1. A random event cannot be known or predicted because there are too many factors that can potentially impact its occurrence. When many random events are observed over a long period of time, a noticeable pattern can emerge. For example, in this particular experiment, it can be said that each temperature reading that was taken during each two-hour time interval is an individually random event. Each reading is random in the sense that there is no way of knowing exactly what degree the thermometer will read at any given time because of the unpredictable and often unavoidable factors that may or may not influence the experiment’s outcome; however, if a large group of readings is studied over a period of time, a pattern may be established, thus making it slightly more possible to predict an outcome.

A systematic event is best explained by bias, which can occur when one or more possible events exert systematic effects in an experiment and as a result, greatly alter the outcome. Like a random event, systematic events cannot be predicted, although they are often temporary. They are events that are to be expected in any type of experiment, as they are products of the experiment itself. For example, a couple of the temperature readings taken over the five-day period may be influenced by physiological factors, such as natural hormonal changes or a sudden onset of illness.

Temperature Fluctuation Graph

3. There were a few systematic effects present in our experiment, as well as randomness. One of the systematic effects that was present was the influence of drinking a hot beverage immediately prior to taking the temperature reading. On two occasions, I sipped on coffee right before taking my temperature; therefore, my temperature was most likely influenced by the heat that resonated in my mouth as a result of the hot coffee. This idea is exemplified on the graph in the 6:00pm-8:00pm interval on Friday, Jan. 18th, where my temperature read 99.0 degrees Fahrenheit, and also in the 4:00pm-6:00pm interval on Saturday, Jan. 19th, where my temperature read 99.1 degrees Fahrenheit. As you can see from the other blue points on the graph, the two temperature readings I have just outlined are significantly higher than the others.

Another systematic effect that impacted the outcome of our experiment is the simple fact that my partner and I were using two completely different thermometers to take our readings. Because one thermometer could be more sensitive than another, we cannot assume that one partner’s temperature fluctuation follows a similar trend as the other’s unless the same thermometer was to be used for both partners.

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